WikiPedia: BinomialDistribution

Difference (from prior author revision) (major diff, minor diff)

Changed: 3c3

To get a result of X heads in a sequence of N tosses, several things have to happen. If the probability of a head on a single trial is p and the probability of a tail is q (1-p), then X heads and N-X tails has a probability calculated by multiplying X p's times N-X q's or (p^X q^(N-X)). However, there are many sequences which match this description. By the methods of CombinaTorics, we can find that there are N!/X!/(N-X)! different combinations with X heads and N-X tails. So, the probability of X heads is

To get a probability of getting X heads in a sequence of N tosses, several things have to happen. If the probability of a head on a single trial is p and then the probability of a tail is q=(1-p) Then the result of X heads and N-X tails on any one trial has a probability calculated by finding the product of multiplying p times itself X times (p^X), and q times itself (N-X) times (q^(N-X)), that is (p^X q^(N-X)). However, there are many sequences which match this description. By the methods of CombinaTorics, we can find that there are N!/(X!*(N-X)!) different combinations with X heads and N-X tails. So, the probability of X heads is

Changed: 5c5

N!/X!/(N-X)! p^X q^(N-X)

N!/(X!*(N-X)!) p^X q^(N-X)

Changed: 7c7,11

[RABeldin]

To the author:
First q=1-p, but more important your formula the probabilty of X heads out of N trials is WRONG.
See BinomialDistribution/Revisited
RoseParks

The Binomial distribution can be described as the sum of a specific number of independent trials, each of which results in either a zero or a one with constant probability. It provides a reasonable description of coin tossing experiments, among others.

   N!/(X!*(N-X)!) p^X q^(N-X)

[RABeldin]

To the author: First q=1-p, but more important your formula the probabilty of X heads out of N trials is WRONG. See BinomialDistribution/Revisited RoseParks