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Revision 27 . . (edit) December 6, 2001 9:16 am by (logged).123.179.xxx [*minor fixes]
Revision 26 . . December 6, 2001 7:18 am by (logged).123.179.xxx
Revision 25 . . December 6, 2001 3:08 am by AxelBoldt
Revision 24 . . December 6, 2001 2:11 am by (logged).123.179.xxx [*Added replies.]
Revision 23 . . December 6, 2001 12:23 am by AxelBoldt [Is force a bound vector or not? Is position a vector?]
Revision 22 . . December 5, 2001 9:44 am by (logged).123.179.xxx [*explained edit, commented on horse pucky vectors in physics comment.]
Revision 21 . . September 20, 2001 11:57 am by (logged).144.199.xxx [n-tuples are not vectors...]
  

Difference (from prior major revision) (minor diff)

Changed: 23c23
:Position, at least in 3-space, is represented as: (x, y, z), right? What is the difference between using that and [x y z]? Position, you might say, is implicitly a vector. Distance is not. If a position vector is r then distance = |r| or |δr| (δr, by the way, is displacement).
:Position, at least in 3-space, is represented as: (x, y, z), right? What is the difference between using that and [x y z]? Position, you might say, is implicitly a vector. Distance is not. If a position vector is r then distance = |r| or |Δr| (Δr, by the way, is displacement).

Added: 146a147,166
:::Is there any other way to defin position but as desplacement from the origin?

:::I suppose that position is unique in that respect (not being additive), because I tried to come up with a good mathematical definition of bound vector from the example, and this is the best I could come up with:

When transforming from one reference frame to another that is related to the first by only a translation, the following occurse:

  1. True vectors do not transform.
  2. Pure pseudovectors do not transform.
  3. Pure bound vectors transform thus:
    ::anew = aold - btransform


When the transformation only involves a change in handedness (i.e. the transformation matrix is something of the form
[±1 0 0]
[0 ±1 0]
[0 0 ±1]):

  1. True vectors transform via multipliction with the matrix
  2. Pure bound vectors do the same
  3. pseudo-vectors do not transform (even though they point in the opposite direction).

Maybe this will clear things up.--BlackGriffen

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