[Home]History of Bilinear operator

HomePage | Recent Changes | Preferences

Revision 4 . . October 5, 2001 1:30 am by AxelBoldt [expanded a little on examples]
Revision 3 . . October 4, 2001 3:52 pm by (logged).115.22.xxx [examples]
  

Difference (from prior major revision) (no other diffs)

Changed: 22,23c22


Examples

Examples




Changed: 25,28c24,30
* If a vector space over the real numbers, R, has an inner product, then it is a bilinear operator.
* The application operator, b(f, v) = f(v) is a bilinear operator from V*xV.
* Let f be a member of V* and g a member of W*. Then b(v, w) = f(v)g(w) is a bilinear operator.
* In R2, assign to each two vectors the signed area of the parallelogram they define.
One often thinks of a bilinear operator as a generalized "multiplication" which satisfies the [distributive law]?.

* Matrix multiplication is a bilinear map M(m,n) x M(n,p) -> M(m,p).
* If a vector space V over the real numbers R carries an inner product, then the inner product is a bilinear operator V x V -> R.
* If V is a vector space with dual space V*, then the application operator, b(f, v) = f(v) is a bilinear operator from V*xV to the base field.
* Let V and W be vector spaces over the same base field F. If f is a member of V* and g a member of W*, then b(v, w) = f(v)g(w) defines a bilinear operator V x W -> F.
* The cross product in R3 is a bilinear operator R3 x R3 -> R3.

Changed: 30c32
* The operator B: VxW -> X where B(v, w) = 0 is bilinear
* The operator B: VxW -> X where B(v, w) = 0 for all v in V and w in W is bilinear

HomePage | Recent Changes | Preferences
Search: