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Revision 2 . . November 6, 2001 4:12 am by DrBob [reply]
Revision 1 . . November 6, 2001 3:57 am by Sodium [I thought that when using SI units it was unnecesary to put in these constants as the system is designed around them ]
  

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Added: 1a2,4

SI doesn't eliminate the constant in this case. It does for F=ma, for instance (this is F=kma in other unit systems) but not for F=k/r^2. In this case k=-G M1 M2,
where G is 'big G', the gravitational constant, and M1 and M2 are the masses of the gravitating bodies. -- DrBob

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